[ad_1]
This month’s Train challenges you to swapping variables values with out utilizing a 3rd variable. It’s an answer broadly obtainable on the Web, however your job is to determine the approach with out wanting elsewhere.
I confess that I noticed this answer months in the past and marveled at it. However I forgot the specifics. Somewhat than look it up once more, I got down to devise it alone, utilizing solely my imprecise reminiscence of the mathematical operations used on the 2 variables to swap values. Listed here are the three statements I exploit:
Swapping Variables Values
b = b + a;
a = b - a;
b = b - a;
Sure, it took me some time to hone this end result, which works for each signed and unsigned values. Determine 1 helps illustrate how the operation works.
Successfully, variable b
turns into what would in any other case be swapping variable c
. First it holds the sum of a
and b
: b = b + a
When authentic a
is subtracted, what’s left over is b
, which is assigned to a
: a = b - a
Lastly, the brand new worth of a
(authentic b
) is subtracted from new b
, which yields the unique worth of a
, assigned to b
: b = b - a
It took my mind a couple of minutes to just accept this answer. I even tried to condense it to solely two statements, however both I’m not that sensible or such an answer isn’t doable. Regardless, right here is the total answer:
2023_06-Train.c
#embody <stdio.h> int principal() { int a,b; printf("Enter worth A: "); scanf("%d",&a); printf("Enter worth B: "); scanf("%d",&b); printf("Earlier than: A=%d, B=%dn",a,b); b = b + a; a = b - a; b = b - a; printf("After: A=%d, B=%dn",a,b); return(0); }
After scripting this code, I checked the interwebs to see what I discovered earlier, the inspiration for this Train. Yep, I bought it proper. I hope you probably did as nicely.
You can also Read : Enforced Bounds Checking for Frozen Perform Interfaces
[ad_2]